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Let S = {1, 2, 3, 4}. The total number of unordered pairs of disjoint subsets of S is equal to
  [JEE 2010]
  • a)
    25
  • b)
    34
  • c)
    42
  • d)
    41
Correct answer is option 'D'. Can you explain this answer?
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Let S = {1, 2, 3, 4}. The total number of unordered pairs of disjoint ...
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Let S = {1, 2, 3, 4}. The total number of unordered pairs of disjoint ...
Explanation:

Given:
S = {1, 2, 3, 4}

Finding the number of unordered pairs of disjoint subsets:
To find the number of unordered pairs of disjoint subsets of S, we first need to find the total number of subsets of S.

Finding the total number of subsets of S:
The number of subsets of a set with n elements is given by 2^n.
For S = {1, 2, 3, 4}, n = 4
Therefore, the total number of subsets of S = 2^4 = 16

Finding the number of unordered pairs of disjoint subsets:
For any given set, the number of ways to form two disjoint subsets is 3^n, where n is the number of elements in the set.
So, for S = {1, 2, 3, 4}, the number of unordered pairs of disjoint subsets = 3^4 = 81
However, this includes ordered pairs, so we need to subtract the number of ordered pairs.
The number of ordered pairs can be found by multiplying the number of ways to choose a subset from 16 subsets for the first subset and 15 subsets for the second subset.
So, the number of ordered pairs = 16 * 15 = 240
Therefore, the total number of unordered pairs of disjoint subsets = 81 - 240 = 41
Therefore, the correct answer is option 'D' - 41.
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